heywatchthis
Well-known member
- Joined
- Feb 28, 2005
- Posts
- 199
I know, I know everyone is sick of this. And yes I did do a search and found tons of info previously discussed.
Background?
An obstacle-free departure flight path is based on your aircraft climbing at least 200 feet per nautical mile, after it crosses the end of the runway at least 35 feet above the ground. In addition, you must be able to climb to 400 feet above the airport elevation within 2 nautical miles, before reaching a point where a turn is required. (IE 200 FPNM)
ALSO?
A slope of 152 feet per nautical mile is assessed for obstacles. If no obstacle penetrates this slope, the 200 feet per nautical mile climb gradient provides you with a minimum of 48 feet of obstacle clearance for each mile of flight. If obstacles do penetrate this slope, special avoidance procedures such as ceiling and visibility minimums, detailed flight maneuvers, and/or greater climb gradients are specified.
QUESTION?
If there is an obstacle just under the 152 fpnm (say 150 fpnm), then you will have no indication of an obstacle and it is considered an obstacle free departure flight path.
BUT in order to make the standard 200 fpnm requirement to 400 ft, you would need a climb gradient of 3.29%. (200 / 6076 *100)
If you take off at a weight that gives you the minimum climb gradient for 2nd segment climb of 2.4% gross, and a 1.6% net, seeing how you know of no obstacles...
YOU WILL NOT BE ANYWHERE NEAR 3.3% AND COULD HIT THE OBSTACLE.
So why the heck do we need to make a minimum 2.4 % climb, when obstacles are assessed up to 3.3% climb gradient with no warning?
Background?
An obstacle-free departure flight path is based on your aircraft climbing at least 200 feet per nautical mile, after it crosses the end of the runway at least 35 feet above the ground. In addition, you must be able to climb to 400 feet above the airport elevation within 2 nautical miles, before reaching a point where a turn is required. (IE 200 FPNM)
ALSO?
A slope of 152 feet per nautical mile is assessed for obstacles. If no obstacle penetrates this slope, the 200 feet per nautical mile climb gradient provides you with a minimum of 48 feet of obstacle clearance for each mile of flight. If obstacles do penetrate this slope, special avoidance procedures such as ceiling and visibility minimums, detailed flight maneuvers, and/or greater climb gradients are specified.
QUESTION?
If there is an obstacle just under the 152 fpnm (say 150 fpnm), then you will have no indication of an obstacle and it is considered an obstacle free departure flight path.
BUT in order to make the standard 200 fpnm requirement to 400 ft, you would need a climb gradient of 3.29%. (200 / 6076 *100)
If you take off at a weight that gives you the minimum climb gradient for 2nd segment climb of 2.4% gross, and a 1.6% net, seeing how you know of no obstacles...
YOU WILL NOT BE ANYWHERE NEAR 3.3% AND COULD HIT THE OBSTACLE.
So why the heck do we need to make a minimum 2.4 % climb, when obstacles are assessed up to 3.3% climb gradient with no warning?