Okay very important mental math problem here (NOT!) but interesting....
Most of the time we descend gradually...on an ILS 3deg but for those of you who land so hard it feels like you are dropping out of the sky here is how you can figure out "how far you were dropped from"
*since no "square" sign anything squared will be shown as sq. ie Vsquared will be shown as Vsq
H=Vsq/231580
Where V=vertical speed in ft/min
H=Height in feet from which the aircraft could be dropped from to create the same intensity of touchdown
To Derive
V Finalsq=V initialsq + 2ad
Where V Final = Touchdown speed
V Initial = Zero (dropped from still)
a = acceleration (9.81 meters/second sq)
d = height (h) we are solving for
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.