VNugget
suck squeeze bang blow
- Joined
- Dec 4, 2002
- Posts
- 809
Descending while inverted does ont negate my argument, since it wasn't based on that. I said IF you don't happen to have enough thrust to overcome the drag, (do you know if that would be the case? I don't) then you can add to your thrust vector by descending.Thedude said:Speed is important, but I assume that for disscusion purposes we are talking about steady state flight, straight and level. So descending while inverted would negate your argument. That is not flying inverted that is descending inverted.
The short version is CL=1/2 Rho V*2. So according to this, I can shove a rocket engine in my car and fly it around because I have now acheived V=velocity. I am talking real world , make it happen and show me kinda physics when I speak of the 152. Not enough thrust = not enough velocity.
Region of Reverse command is not mysterious regime. Every time I land my B-727 the approach is done in the area of reverse command as you will find with most transport cat a/c.
Cl does not equal 1/2*rho*V^2 (I assume you meant to use use * as an exponent).
Cl = L / ((1/2)*rho*V^2*S)
or,
L = Cl*(1/2)*rho*V^2*S
Like I said, if you don't have enough Cl, you can make up for it with V. (Even in a descent. Getting some of your weight to add to your thrust does not mean that a wing is "not flying" anymore.) Which brings me to my next point. You implied that with an inverted airfoil, the only way this can work if you add some ridiculous amount of V to make up for a miniscule Cl, as per your car/rocket example.
Thanks but no thanks... let's do some actual investigation. Let's look at the airfoil data obtained expirementally by NACA in the 50's* for a sipmle cambered airfoil. Say, 2412 for example. In the positive AOA range, the Cl tops out at about 1.6, and in the negative range, at about -0.9, so the negative Clmax is about .56 of the positive. To maintain the same lift we'd have to multiply (V^2) by the reciprocal, or 1.77. The square root of that is about 1.33. Blah blah blah, get to the point? For an infinite NACA 2412 airfoil, stall speed increases by .33** if you invert it. Do you need to strap a rocket engine on to do be able to do that? Don't think so.
* Reference: Introduction to Flight, John D. Anderson, Jr. I tried to look for this stuff online, but couldn't find it. If you want, I'll scan the graphs for you.
** Incidentally, this means you big jet jocks can still fly almost the same approach speed inverted as upright, you just can't flare.
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