VNugget gave you the right explanation but as User997 mentioned you're thinking in the right direction. There are two pieces that must be connected in the scenario you just described: longitudinal stability and power. The stability curve will plot the moment about the lateral axis as a function of coefficient of lift. For a certain configuration of the elevator and trim there is a value of CL that results in a zero moment, this is what we typically call the trimmed condition. If the aircraft is distrurbed it will seek out that value of CL that results in the equilibrium condition. So if you lift the nose to increase the AOA then release the yoke, the increased lift behind the CG will create a nose down moment, restoring the original AOA. If you push the nose down and release the yoke, the decreased AOA will result in less lift behind the CG and a nose up moment, thus restoring the original AOA. Of course this assumes positive stability
But in straight and level flight a particular AOA corresponds to a particular airspeed. The other piece is the power available versus power required at a particular airspeed. At a particular airspeed you can either climb, descend, or fly straight and level depending on the power available. In your example you pull the power and suddenly there is insufficient thrust to overcome drag. The plane then slows, which reduces the lift. The nose then pitches over because of the reduced moment contributed by the lift. As the nose pitches over the airspeed will probably build but as the plane descends the air comes more from underneath as you mentioned, increasing the AOA. Just because the AOA increases due to the increased relative wind coming from under the plane doesn't mean it reaches critical AOA. If you haven't changed the trim the plane will want to maintain the same AOA as it had before you pulled the power and will oscillate until it does reach it.
The plane also wants to balance the forces on it and left to its own devices it will seek to make lift equal weight. Therefore it will assume the value of airspeed that corresponds to that particular value of CL for unaccelerated vertical flight. I used the term unaccelerated vertical flight instead of straight and level flight because a constant rate descent or climb is the equivalent of straight and level flight regarding the forces, in other words L = W. So now the plane has found an AOA and thus a CL to satisfy stability. The plane want equilibrium in the vertical plane so settles on a AOA/airspeed combination to provide that. This airspeed is the airspeed that you had before you pulled the power, at least ofter a few oscillations.
However, you don't have the power required to support that airspeed value so you will either have to descend at that airspeed or fly straight and level at some lower airspeed. Because stability wants to keep the old airspeed you have no choice but to descend. However, the other option is to pull the power and fly at a slower airspeed which is sufficient for that power setting, but to fly hands off you would need to retrim and change the stability equilibrium point.
Dave
But in straight and level flight a particular AOA corresponds to a particular airspeed. The other piece is the power available versus power required at a particular airspeed. At a particular airspeed you can either climb, descend, or fly straight and level depending on the power available. In your example you pull the power and suddenly there is insufficient thrust to overcome drag. The plane then slows, which reduces the lift. The nose then pitches over because of the reduced moment contributed by the lift. As the nose pitches over the airspeed will probably build but as the plane descends the air comes more from underneath as you mentioned, increasing the AOA. Just because the AOA increases due to the increased relative wind coming from under the plane doesn't mean it reaches critical AOA. If you haven't changed the trim the plane will want to maintain the same AOA as it had before you pulled the power and will oscillate until it does reach it.
The plane also wants to balance the forces on it and left to its own devices it will seek to make lift equal weight. Therefore it will assume the value of airspeed that corresponds to that particular value of CL for unaccelerated vertical flight. I used the term unaccelerated vertical flight instead of straight and level flight because a constant rate descent or climb is the equivalent of straight and level flight regarding the forces, in other words L = W. So now the plane has found an AOA and thus a CL to satisfy stability. The plane want equilibrium in the vertical plane so settles on a AOA/airspeed combination to provide that. This airspeed is the airspeed that you had before you pulled the power, at least ofter a few oscillations.
However, you don't have the power required to support that airspeed value so you will either have to descend at that airspeed or fly straight and level at some lower airspeed. Because stability wants to keep the old airspeed you have no choice but to descend. However, the other option is to pull the power and fly at a slower airspeed which is sufficient for that power setting, but to fly hands off you would need to retrim and change the stability equilibrium point.
Dave
UnAnswerd said:Thank you all for the informative replies. Let me just try this scenario:
In staight and level flight, I reach over and turn the ignition off. The airspeed starts to drop to stall speed, but I do not touch the yoke. Instead, I just let the nose go over. Is this not a stall? I never touched the yoke, so I assume the angle between the wing chord-line and the relative wind never exceeded the citical limit? Is this not a stall at a low AOA???
EDIT: Or maybe I am wrong. Maybe when the nose goes over and the airplane starts to sink, relative wind hits the airplane from more-less underneith it, and certainly that would exceed the critical AOA....