CutEmUp said:
I think that the reason launching from the equator is more efficient is not because it gets "thrown" off of the earths surface faster. It is because there is less gravity at the equater.
Since the earth is a slightly squashed sphere, the center of the earth (center of mass) is furthest from the launch site when that sight is at the equater. And since the force of gravity varies inversley with the distance from the center of mass squared, there is less gravity at the equater, or on top of a mountain for that matter.
The Earth's surface is a gravitational equipotential surface. What that means is that the (mean sea level) surface of the earth is at a level where the gravitational force + centrifugal force is equal all over the surface. This is the reason why the Earth is squashed like an oblate spheroid. So, two locations on the earth, both at MSL, both experience the same perceived gravity. Otherwise, the water would "slosh" to the place with greater gravity. So, in effect, the water "self-levels" to match a gravitational equipotential surface. Most launch complexes are near-sea-level (because being next to the ocean gives you a good place to dup stages), so they are all at pretty much at the bottom of the same gravitational well (Baikanour, on the Kazakh steppes, being the possible exception, but I still think you won't see much benefit, as the Kinetic Energy you must impart to accelerate a spacecraft to 17,600 mph is MUCH greater than the energy saved by starting it out a few thousand feet out of Earth's gravitational well).
Read up on the WGS84 ellipsoid that GPS systems use as a reference surface for the Earth. It is an equipotential surface, more or less.
Now, consider the fact that, to orbit something, I must accelerate it to 17,600 mph. Getting the first 1,037 mph from the earth's rotation (its rotational speed at the equator) is no small matter.
EDIT - in the case of the earth's gravitational equipotential surface, it is usually referred to as a geopotential surface, or geoid. It is actually NOT a perfect ellipsoid, due to mass concentrations, but the sea level does correspond to it.
http://en.wikipedia.org/wiki/Geopotential
http://en.wikipedia.org/wiki/Geoid