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Net t/o flight path - 2nd seg ?

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tathepilot

Well-known member
Joined
Oct 5, 2003
Posts
884
I'm trying to figure out how to convert a net climb gradient percentage to a required minimum climb per NM for the SQUAT ONE RNAV DEPARTURE (SQUAT1.SQUAT) @ KRIL

The aircraft has a 3.5% Net climb gradient.



RIFLE, CO
GARFIELD COUNTY RGNL
TAKE-OFF MINIMUMS: Rwy 8, 5500-3 or std. with a min.
climb of 370' per NM to 13000. Rwy 26, 3400-3 or std.
with a min. climb of 360' per NM to 10000.
DEPARTURE PROCEDURE: Rwy 8, DME required.
Climb via RIL R-081 to 10 DME, then climbing left turn
direct RIL VOR/DME. Climb in RIL VOR/DME holding
pattern (Hold E, right turns, 263° inbound) to cross
RIL VOR/DME at or above 13000 before proceeding
enroute; or, as cleared by ATC. Rwy 26, use SQUAT RNAV DEPARTURE


I need to figure this out by tomorrow, thanks.!
 
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Give this a shot...

(3.5/100) x 6076 = 212.66' / nm... If my math serves me right...

Edit: But now that I'm reading what you wrote, does the SQUAT departure require 3.5% climb gradient? Or are you saying that your aircraft will produce a 3.5% climb gradient??? And the climb gradient that an aircraft produces is dependent on several things. I'm kinda lost with the info you've provided...
 
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I pulled out the Net T/O flight path - 2nd segment chart for the aircraft, and based on simulated conditions that were given to me, the a/c can produce a 3.5% net climb gradient.

The dp requires 360 feet per nm. @ a climb ground speed of 150 that equates to 900 fpm.

I hope that helps. So you see, I'm trying to figure out if a 3.5% net climb gradient will equal 900 fpm or better..

Am I missing something..?
 
Give this a shot...

(3.5/100) x 6076 = 212.66' / nm... If my math serves me right...

Edit: But now that I'm reading what you wrote, does the SQUAT departure require 3.5% climb gradient? Or are you saying that your aircraft will produce a 3.5% climb gradient??? And the climb gradient that an aircraft produces is dependent on several things. I'm kinda lost with the info you've provided...


Thanks.!!
 
Put 3.5 on the outside scale of your whiz wheel over 10 on the inside, and read ft/mile over the speed cursor... ;)

Fly safe!

David
 
whiz wheel, what the heck is that... lol
It's the second-easiest way to answer your question...the easiest would be to look under 100 knots in the rate of climb table and read 592, move the decimal point two places to the left, and get 5.92% climb gradient required.

Fly safe!

David
 
sorry I don't have a whiz wheel anymore... It's all good, doing an ATP type... the performance class that my company gave was half-azz so it was hard for me to understand the finer points...

that is not an excuse, i know that im not perfect, my oral was rescheduled a week earlier so i needed the help and i got it so thanks...!!!!
 
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As far as I know, there are three of us in the entire world that still carry one...just didn't know you weren't one of us. ;)

Fly safe!

David
 
It's the second-easiest way to answer your question...the easiest would be to look under 100 knots in the rate of climb table and read 592, move the decimal point two places to the left, and get 5.92% climb gradient required.

Fly safe!

David

wow, extremely accurate.. thx.
 
Rise over run = percentage

360 divided by 6076 = .0059249 X 100 yields 5.92%


Percentage X run divided by 100 = rise

5.92 X 6076 = 35969.92 divided by 100 = 359.6992 or 360

Substitute your 3.5%

3.5 X 6076 = 21266 divided by 100 = 212.66

Two important equations you should store in your brains hard drive.
 
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Rise over run = percentage

360 divided by 6076 = .0059249 X 100 yields 5.92%


Percentage X run divided by 100 = rise

5.92 X 6076 = 35969.92 divided by 100 = 359.6992 or 360

Substitute your 3.5%

3.5 X 6076 = 21266 divided by 100 = 212.66

Two important equations you should store in your brains hard drive.

Thanks!!
 

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