Question?
I'm not an engineer. Started on it but didn't finish. Got my first REAL flying job instead. Did very well in aerodynamics classes, however, and I'm stumped at one point in your calculations. How are you calculating the speed of the air at the point on the wing at 37000 ft after you have calculated aircraft TAS? And...are you taking into account that 37000 ft lies in the Stratosphere for a Standard Atmosphere? As we all have learned the initial layer of the Stratosphere is isothermal. The density ratio does continue to decrease obviously with decreasing static pressure. Was this accounted for in your calculation?
Now without all the engineering terms. Let's take a hypothetical jet with a published Critical Mach of .87. Let's say at M 0.87 at 30,000 ft, you have Mach 1 flow at a certain point on the wing. You measure and calculate the local SPEED of the flow at that point to be 589 kts. At M 0.8 at 30000, your TRUE airspeed of the aircraft is 512 kts (assuming standard atmosphere). Now, let's climb to 37,000 and hold a Mach of .87. Your true airspeed at this altitude is now 499 kts. Let go back to the the same point on the wing and measure and calculate the speed of the air. We get a value of 557 kts, or M .97.
I'm not an engineer. Started on it but didn't finish. Got my first REAL flying job instead. Did very well in aerodynamics classes, however, and I'm stumped at one point in your calculations. How are you calculating the speed of the air at the point on the wing at 37000 ft after you have calculated aircraft TAS? And...are you taking into account that 37000 ft lies in the Stratosphere for a Standard Atmosphere? As we all have learned the initial layer of the Stratosphere is isothermal. The density ratio does continue to decrease obviously with decreasing static pressure. Was this accounted for in your calculation?