Welcome to Flightinfo.com

  • Register now and join the discussion
  • Friendliest aviation Ccmmunity on the web
  • Modern site for PC's, Phones, Tablets - no 3rd party apps required
  • Ask questions, help others, promote aviation
  • Share the passion for aviation
  • Invite everyone to Flightinfo.com and let's have fun

Cold Air Altimetery

Welcome to Flightinfo.com

  • Register now and join the discussion
  • Modern secure site, no 3rd party apps required
  • Invite your friends
  • Share the passion of aviation
  • Friendliest aviation community on the web

FlyBieWire

Member
Joined
Apr 18, 2006
Posts
21
I can easily understand errors in the altimeter regarding pressure changes, but the errors associated with cold air have me baffeled.

So I do understand, "High to a low, look out below," but not, "Warm to a cold, look out below." Is that true? If so it makes no sense to me.
 
As we go up, air density and temperature both go down at linear rates (usually). From Thermodynamics 101, we know that Pressure = Density x Temperature x (constant r), so pressure is going down as well. Under non-standard conditions, it is possible for temperature to drop faster than usual, while density stays where we expect. This has the effect of lowering pressure, and it is pressure that an altimeter measures. So the altimeter is measuring a low pressure-- which implies a high altitude-- but this is illusory due to the unusually cold air. The plane is not as high as your instrument says it is, look out below.
 
Re-reading my last post, I ought to mention--

The equation I cite is the Ideal Gas Law, and it holds for any gas under conditions that are not too extreme and involve enough molecules of gas. (The points at which the law starts breaking down are way beyond anything that the free atmosphere can produce.) The equation is usually written as

PV=nrT

where P=pressure, V=volume, n=number of gas molecules (moles), r is a constant specific to each gas, and T=temperature. Divide both sides by V and we have

P=(nr/V)T

If we multiply (nr/V) by (molar density of gas/ molar density of gas), which equals 1, we can get

Dr'

where D=density and r' is an adjusted constant. Then,

P=DTr'

which is the equation I used in the previous post.

PV=nrT is easy to remember, and I have found it to be handy to know.
 
Last edited:
Alamanach said:
As we go up, air density and temperature both go down at linear rates (usually).

Not true. Take a look at a table of the pressure values for the standard atmosphere. It is a long way from being a linear function of altitude, even in the idealized standard atmosphere, to say nothing of the real atmosphere.

Alamanach said:
From Thermodynamics 101, we know that Pressure = Density x Temperature x (constant r), so pressure is going down as well. Under non-standard conditions, it is possible for temperature to drop faster than usual, while density stays where we expect. This has the effect of lowering pressure, and it is pressure that an altimeter measures. So the altimeter is measuring a low pressure-- which implies a high altitude-- but this is illusory due to the unusually cold air. The plane is not as high as your instrument says it is, look out below.

I think that you are mis-applying the Ideal gas law. Your explanation breaks down when you consider that very low temperatures are more often than not accompanied by "higher* than normal atmospheric pressure and furthermore your explanation fails to explain why an altimeter, when correctly set to valid altimeter setting indicates lower than actual altitude when aloft.


The real reason: The temperature affects the pressure lapse rate, because it changes the density of the air.

Consider this: If you took a waterproof altimeter and submerged it in water, you would see that you would only have to raise it or lower it about 1 foot in the water to make it show a 1,000 ft change in altitude. The difference in air pressure of 1,000 ft is approximately one inch of mercury, and the difference in water pressure of 13.6 inches is also one inch of mercury. This difference is because water is approximately 1000 times more dense than air.

To get back to the original question, when it's colder, the air is more dense, so a 1"hg difference in pressure may only be 900 ft in the actual atmosphere, But if you ewxperience a 1"hg pressure change your altimeter will still display that as 1000 feet.
 
A Squared said:
Not true. Take a look at a table of the pressure values for the standard atmosphere. It is a long way from being a linear function...

You're right, it's not linear. My bad. Temperature is linear for about the first 30,000 feet, after which it is constant for a while, and after that... well, then it's too high up to matter. The decrease in density is not linear, and this will teach me to be more careful. Page 5 of Aerodynamics for Naval Aviators has a table that spells it out pretty thoroughly.

Page 2 of Aerodynamics for Naval Aviators has an equation toward the end of the page that, I think, supports rather nicely my use of the Ideal Gas Law. By their equation, density is directly proportional to pressure and inversely proportional to temperature; D=P/T, which is saying the same thing as DT=P, which is pretty much what I said.

If, as you point out, lower temperature is associated with higher density, it is because pressure is remaining constant. But constant pressure won't move our altimeter. If temperature changes while density holds constant, then pressure will change, and the altimeter will register that change. It is pressure, not density, that moves the aneroid wafers of the altimeter.

Also, you seem to be saying that cold air makes the altimeter erroneously read a low altitude. If that's the case, (and you would know better than I) then there's some additional phenomenon at work; the basic relationship between temperature, pressure, and density runs in the other direction.
 
New info. for Canadian VNAV approaches

GravityHater said:
What is the r.o.t. for those canadian approaches when it is supercold?? How and what do we adjust?

From the May, 2006 issue of _Avionics News_ (p.23-24):

Canada

Transport Canada Revises Guidance for FMS Designed for VNAV Approaches

TCCA has published Advisory Circular 500-020 to replace ACPL 75 Issue 1, and provide revised guidance on the criteria for incorporation of temperature compensation in new or updated Flight Management System (FMS) designs for barometric Vertical Navigation (VNAV) approach procedures.

Whereas ACPL 57 called for application of temperature compensation for all temperatures, this AC requires temperature compensation only when below International Standard Atmosphere (ISA) conditions exist at the destination airfield. The requirement for above ISA compensation has been suspended pending resolution of operational considerations, promulgation of an operational requirement, and provision of operational guidance and training material.

Other changes reflected in this AC include a clarification that temperature compensation is to be applied to minimum descent altitude/decision altitude of an approach procedure. This is consistent with the current cold temperature compensation procedure in Nav Canada Air Pilot, Canada Air Pilot General Pages (CAP GEN). In addition, the International Civil Aviation Organization "accurate" method has been included as an acceptable means of temperature compensation.

AC 500-020 can be viewed at

www.tc.gc.ca/CivilAviation/certification/guidance/500/500-020.htm
 
Alamanach said:
Page 2 of Aerodynamics for Naval Aviators has an equation toward the end of the page that, I think, supports rather nicely my use of the Ideal Gas Law. By their equation, density is directly proportional to pressure and inversely proportional to temperature; D=P/T, which is saying the same thing as DT=P, which is pretty much what I said.

I didn't say that the Ideal Gas Law was incorrect, nor that it was unrelated. It doen't however, directly explain the phenomenon.

Alamanach said:
If, as you point out, lower temperature is associated with higher density, it is because pressure is remaining constant. But constant pressure won't move our altimeter. If temperature changes while density holds constant, then pressure will change, and the altimeter will register that change. It is pressure, not density, that moves the aneroid wafers of the altimeter.

What you say isn't incorrect, as far as it goes, but it doesn't account for the phenomenon in question. The question (as I interpret it anyway) is not whether the altimeter of a parked airplane will indicate higher in the morning if the temp drops overnight. It may, or it may not, that depends on what the living breathing atmosphere is doing, and there's a lot more factors than just temp change. True, if that airplane was sitting in a closed container in a laboratory, than it would be just like you say. The atmosphere isn't a closed container in a laboratory.

The question, as I understand it is: why is your true altitude lower than your indicated altitude (on an altimeter correectly set to a valid altimeter setting) when the ambient temp is lower than ISA. Now this is only true when your altitude is higher than the station computing the altimeter setting.

If you are sitting on the ramp at the airport where the altimeter setting is measured, your alitmeter will indicate the correct altitude when set to the altimeter setting, regardless of temp. (if it doesn't there's an error in your altimeter, or there's an error in the setting)

Now the reason there is a difference between true altitude and indicated altitude is because of increased air density. I agree that the altimeter doesn't respond to air density, however than is not what i said (or intended to convey) The colder air is denser, and the denser air increases the pressure *lapse rate*, regardless of whether the atmospheric pressure is higher or lower. And as you move up or down through the atmosphere, the altimeter responds to the pressure lapse rate.

The pressure lapse rate is greater with more dense fluids or gasses. My comparison between the pressure lapse rate in air and water in my previous post shows this. Also, if you look at a table of the standard atmosphere, you will see that the pressure lapse rate decreases with altitude and the air density decreases with altitude. The first is a result of the second.

So, the colder air is more dense, which results in an increased pressure lapse rate, so that on a cold day, an altimeter climbing from sea level to 1000' experiences a pressure change of 1.1" of mercury, so the indicated altitude is 1100 ft while the actual altitude is 1000.


Alamanach said:
Also, you seem to be saying that cold air makes the altimeter erroneously read a low altitude. If that's the case, (and you would know better than I) then there's some additional phenomenon at work; the basic relationship between temperature, pressure, and density runs in the other direction.

Yeah, My mistake, I said it would read lower, I meant higher, sorry for the confusion.
 
A Squared said:
What you say isn't incorrect, as far as it goes, but it doesn't account for the phenomenon in question...

Sure it does. If we fly from some ISA air into a body of cold air, but at equal density, then by P=DT, we will see a drop in pressure, which the altimeter will interpret as a gain in altitude, which will be incorrect.

A Squared said:
...denser air increases the pressure *lapse rate*...

OK, I see what you're saying, and that could work if it is as you describe. But why would denser air increase the pressure lapse rate? (I'm not saying it doesn't, you're just off into something I'm not familiar with.)
 
Alamanach said:
If we fly from some ISA air into a body of cold air, but at equal density, then by P=DT, we will see a drop in pressure,

Umm, no, it won't. Not necessarily. You seem to be adamant that the behavior of the atmosphere is absolutely and completely described by the ideal gas law. It's not. As I said before, extrememly cold temperatures are more often than not accompanied by higher than standard temperatures. Now, this is not predicted by the ideal gas law, so you have to conclude that either a) the ideal gas law is incorrect (it is not) or that b) the atmosphere is a little more complicated than one simple equation can completely account for.

Alamanach said:
OK, I see what you're saying, and that could work if it is as you describe. But why would denser air increase the pressure lapse rate? (I'm not saying it doesn't, you're just off into something I'm not familiar with.)

because the pressure lapse rate is directly proportional to the densiy ofh te gas or fluid. I don't have time to give a more complete description right how. I'll try to get back to you a little later, but in the meantime, go back to my description of the altimeter underwater and think it through.
 

Latest resources

Back
Top